WebAnd some of the indexes have duplicate values in the 9th column (the type of DNA repetitive element in this location), and I want to know what are the different types of repetitive elements for individual locations (each index = a genome location). I'm guessing this will require some kind of groupby and hopefully some groupby ninja can help me out. WebJul 31, 2011 · last_occurence=len(yourlist)-yourlist[::-1].index(element)-1 just easy as that.no need to import or create a function. Share. Improve this answer. Follow answered Apr 13, 2024 at 10:09. Prabu M ... Find last index of element in list with duplicate elements python. 0. index() of last occurrence in list in python. 0.
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WebJul 26, 2024 · You can simply use function enumerate (lst) it returns elements index_number and value. for example lst [0] = 1 the case above index_number is 0 and value is 1 so you can just use enumerate function for returning index number using if condition (returns it when the value is 3) WebDec 10, 2024 · You can use enumerate and check the next index in the list. If an element is not equal to the element in the next index, it is the last duplicate: lst = [1, 1, 1, 2, 2, 3, 3, 4, 5] result = [i for i, x in enumerate (lst) if i == len (lst) - 1 or x != lst [i + 1]] print (result) # [2, 4, 6, 7, 8] Share Improve this answer Follow
WebFind an index of duplicate elements in list Python Example Simple example code. a = [1, 2, 3, 2, 1, 5, 6, 5, 5, 5] res = [idx for idx, item in enumerate (a) if item in a [:idx]] print (res) Output: Another example using collections You have … WebFeb 8, 2024 · To repeat the elements in a list in python, we insert the existing elements of a list to the same list. In this way, the elements in a list get repeated. For instance, If we …
WebApr 8, 2024 · Find indexes of consecutive items in lists. and return a 2d list with the indexes of the repeating values: new_list = [] i = 0 while i < len (x)-1: if x [i] == x [i+1]: new_list.append ( [x [i],x [i+1]] i += 1. x is not necessarily sorted but has at least one series of repeating values. For example x can also be:
WebJun 9, 2011 · You can use a list comprehension with enumerate: indices = [i for i, x in enumerate (my_list) if x == "whatever"] The iterator enumerate (my_list) yields pairs (index, item) for each item in the list. Using i, x as loop variable target unpacks these pairs into the index i and the list item x.
WebMar 31, 2024 · This program uses the numpy library to convert a given list into an array, finds the indices of the given value in the array, and converts the resulting numpy array back to a list. Finally, it prints the list of indices. Python3 import numpy as np test_list = [1, 3, 4, 3, 6, 7] test_array = np.array (test_list) european conference on complex systems eccsWebOct 7, 2008 · @stefanct this likely does double the complexity, I believe the in operator on a list has linear runtime. @ApproachingDarknessFish stated it would iterate twice which answers your question, and is right in saying that doubling the linear complexity is … european concepts williamsburg vaWebDec 16, 2024 · There are much more efficient ways of finding duplicates in list in python (yours is O(n^2)), and its probably just better using numpy library to do it: import numpy … european concealed hingesWebOct 12, 2024 · How can I find all the indexes of a recurring item? For Example: list = ['A', 'A', 'B', 'A', 'B', 'B', 'A'] I want to return all occurrences of 'B', so it'd return: indexes = [2, 4, 5] python python-3.x list Share Improve this question Follow edited Apr 18, 2024 at 15:56 Tomerikoo 17.9k 16 45 60 asked Oct 12, 2024 at 5:22 desiigner 79 1 3 10 1 european company store solar panelsWebJan 18, 2014 · As per the str.index docs, signature looks like this. str.index(sub[, start[, end]]) The second parameter is the starting index to search from. So you can pass the index which you got for the first item + 1, to get the next index. first aid for wasp stingWebApr 25, 2015 · You can use the count () method from the list object to get a count equal to 1: >>> A= [1, 2, 3, 2, 5, 1] >>> unique= [i for i in A if A.count (i)==1] >>> unique [3, 5] Alternatively the Counter () class from the collections module can be used: A = [1, 2, 3, 2, 5, 1] c = Counter (A) print [key for key, count in c.iteritems () if count==1] Share first aid for woundWebAug 22, 2024 · How do I get the index of a duplicated string in a list? Traversing through the length of the list so that we can keep a track of each index and print the index. … european conference on computer vision出版社